Base | Representation |
---|---|
bin | 1010010001110011100010… |
… | …1101001101010100010111 |
3 | 1111000100212211200211111121 |
4 | 2210130320231031110113 |
5 | 2440123432121042103 |
6 | 40011340143344411 |
7 | 2244320366605066 |
oct | 244347055152427 |
9 | 44010784624447 |
10 | 11301010330903 |
11 | 3667805795827 |
12 | 13262655b2107 |
13 | 63c8b06691a7 |
14 | 2b0d869541dd |
15 | 148e728da6bd |
hex | a4738b4d517 |
11301010330903 has 2 divisors, whose sum is σ = 11301010330904. Its totient is φ = 11301010330902.
The previous prime is 11301010330873. The next prime is 11301010330921. The reversal of 11301010330903 is 30903301010311.
11301010330903 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11301010330903 - 213 = 11301010322711 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11301010330963) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5650505165451 + 5650505165452.
It is an arithmetic number, because the mean of its divisors is an integer number (5650505165452).
Almost surely, 211301010330903 is an apocalyptic number.
11301010330903 is a deficient number, since it is larger than the sum of its proper divisors (1).
11301010330903 is an equidigital number, since it uses as much as digits as its factorization.
11301010330903 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 729, while the sum is 25.
The spelling of 11301010330903 in words is "eleven trillion, three hundred one billion, ten million, three hundred thirty thousand, nine hundred three".
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