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113010122130233 is a prime number
BaseRepresentation
bin11001101100100000111000…
…001011111000001100111001
3112211010122212201101112212112
4121230200320023320030321
5104303024212231131413
61040204044451422105
732542466114461466
oct3154407013701471
9484118781345775
10113010122130233
1133010361858159
12108121512b4935
134b09a68bb0223
141dc9a0d2ac66d
15d0e9bc8db2a8
hex66c8382f8339

113010122130233 has 2 divisors, whose sum is σ = 113010122130234. Its totient is φ = 113010122130232.

The previous prime is 113010122130223. The next prime is 113010122130239. The reversal of 113010122130233 is 332031221010311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 68891792811664 + 44118329318569 = 8300108^2 + 6642163^2 .

It is a cyclic number.

It is not a de Polignac number, because 113010122130233 - 210 = 113010122129209 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 113010122130199 and 113010122130208.

It is not a weakly prime, because it can be changed into another prime (113010122130239) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56505061065116 + 56505061065117.

It is an arithmetic number, because the mean of its divisors is an integer number (56505061065117).

Almost surely, 2113010122130233 is an apocalyptic number.

It is an amenable number.

113010122130233 is a deficient number, since it is larger than the sum of its proper divisors (1).

113010122130233 is an equidigital number, since it uses as much as digits as its factorization.

113010122130233 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 648, while the sum is 23.

Adding to 113010122130233 its reverse (332031221010311), we get a palindrome (445041343140544).

The spelling of 113010122130233 in words is "one hundred thirteen trillion, ten billion, one hundred twenty-two million, one hundred thirty thousand, two hundred thirty-three".