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113010123331327 is a prime number
BaseRepresentation
bin11001101100100000111000…
…010000011101011011111111
3112211010122212210122120110111
4121230200320100131123333
5104303024213033100302
61040204044533250451
732542466130623305
oct3154407020353377
9484118783576414
10113010123331327
11330103624a85a2
1210812151793a27
134b09a69210b31
141dc9a0d502275
15d0e9bca770d7
hex66c83841d6ff

113010123331327 has 2 divisors, whose sum is σ = 113010123331328. Its totient is φ = 113010123331326.

The previous prime is 113010123331253. The next prime is 113010123331349. The reversal of 113010123331327 is 723133321010311.

It is a strong prime.

It is an emirp because it is prime and its reverse (723133321010311) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-113010123331327 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (113010133331327) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56505061665663 + 56505061665664.

It is an arithmetic number, because the mean of its divisors is an integer number (56505061665664).

Almost surely, 2113010123331327 is an apocalyptic number.

113010123331327 is a deficient number, since it is larger than the sum of its proper divisors (1).

113010123331327 is an equidigital number, since it uses as much as digits as its factorization.

113010123331327 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6804, while the sum is 31.

Adding to 113010123331327 its reverse (723133321010311), we get a palindrome (836143444341638).

The spelling of 113010123331327 in words is "one hundred thirteen trillion, ten billion, one hundred twenty-three million, three hundred thirty-one thousand, three hundred twenty-seven".