Base | Representation |
---|---|
bin | 1010010001110011100101… |
… | …0110011001111001011010 |
3 | 1111000100220121000111112101 |
4 | 2210130321112121321122 |
5 | 2440123442402132310 |
6 | 40011341211034014 |
7 | 2244320560444231 |
oct | 244347126317132 |
9 | 44010817014471 |
10 | 11301021130330 |
11 | 36678108a1578 |
12 | 132626913b90a |
13 | 63c8b297a899 |
14 | 2b0d88165b18 |
15 | 148e7382043a |
hex | a4739599e5a |
11301021130330 has 16 divisors (see below), whose sum is σ = 20351474187264. Its totient is φ = 4518267084880.
The previous prime is 11301021130319. The next prime is 11301021130337. The reversal of 11301021130330 is 3303112010311.
It is a junction number, because it is equal to n+sod(n) for n = 11301021130298 and 11301021130307.
It is not an unprimeable number, because it can be changed into a prime (11301021130337) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 267648742 + ... + 267690961.
It is an arithmetic number, because the mean of its divisors is an integer number (1271967136704).
Almost surely, 211301021130330 is an apocalyptic number.
11301021130330 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
11301021130330 is a deficient number, since it is larger than the sum of its proper divisors (9050453056934).
11301021130330 is a wasteful number, since it uses less digits than its factorization.
11301021130330 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 535341821.
The product of its (nonzero) digits is 162, while the sum is 19.
Adding to 11301021130330 its reverse (3303112010311), we get a palindrome (14604133140641).
The spelling of 11301021130330 in words is "eleven trillion, three hundred one billion, twenty-one million, one hundred thirty thousand, three hundred thirty".
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