Base | Representation |
---|---|
bin | 10101000011001100… |
… | …00000100011100001 |
3 | 1002011120212210220212 |
4 | 22201212000203201 |
5 | 141121030430423 |
6 | 5105220143505 |
7 | 550023112442 |
oct | 124146004341 |
9 | 32146783825 |
10 | 11301030113 |
11 | 487a15620a |
12 | 2234837b95 |
13 | 10b13c6289 |
14 | 792c712c9 |
15 | 462203578 |
hex | 2a19808e1 |
11301030113 has 4 divisors (see below), whose sum is σ = 11368701120. Its totient is φ = 11233359108.
The previous prime is 11301030107. The next prime is 11301030131. The reversal of 11301030113 is 31103010311.
It is a happy number.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 11301030113 - 26 = 11301030049 is a prime.
It is a super-2 number, since 2×113010301132 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (11301030173) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 33835253 + ... + 33835586.
It is an arithmetic number, because the mean of its divisors is an integer number (2842175280).
Almost surely, 211301030113 is an apocalyptic number.
It is an amenable number.
11301030113 is a deficient number, since it is larger than the sum of its proper divisors (67671007).
11301030113 is an equidigital number, since it uses as much as digits as its factorization.
11301030113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 67671006.
The product of its (nonzero) digits is 27, while the sum is 14.
Adding to 11301030113 its reverse (31103010311), we get a palindrome (42404040424).
The spelling of 11301030113 in words is "eleven billion, three hundred one million, thirty thousand, one hundred thirteen".
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