11301032113141 has 4 divisors (see below), whose sum is σ = 11387299533984. Its totient is φ = 11214764692300.

The previous prime is 11301032113121. The next prime is 11301032113157. The reversal of 11301032113141 is 14131123010311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11301032113141 - 2²³ = 11301023724533 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11301032113121) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 43133710225 + ... + 43133710486.

It is an arithmetic number, because the mean of its divisors is an integer number (2846824883496).

Almost surely, 2^{11301032113141} is an apocalyptic number.

It is an amenable number.

11301032113141 is a deficient number, since it is larger than the sum of its proper divisors (86267420843).

11301032113141 is an equidigital number, since it uses as much as digits as its factorization.

11301032113141 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 86267420842.

The product of its (nonzero) digits is 216, while the sum is 22.

Adding to 11301032113141 its reverse (14131123010311), we get a palindrome (25432155123452).

The spelling of 11301032113141 in words is "eleven trillion, three hundred one billion, thirty-two million, one hundred thirteen thousand, one hundred forty-one".