Base | Representation |
---|---|
bin | 11001101100100001110011… |
… | …101010100111110111111111 |
3 | 112211010202110021010220100201 |
4 | 121230201303222213313333 |
5 | 104303033233212424232 |
6 | 1040204331500304331 |
7 | 32542532622560602 |
oct | 3154416352476777 |
9 | 484122407126321 |
10 | 113011120045567 |
11 | 33010824087777 |
12 | 1081238b5420a7 |
13 | 4b09b9786a583 |
14 | 1dc9aa5a36339 |
15 | d0ea2a309be7 |
hex | 66c873aa7dff |
113011120045567 has 2 divisors, whose sum is σ = 113011120045568. Its totient is φ = 113011120045566.
The previous prime is 113011120045531. The next prime is 113011120045639. The reversal of 113011120045567 is 765540021110311.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-113011120045567 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (113011120045667) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56505560022783 + 56505560022784.
It is an arithmetic number, because the mean of its divisors is an integer number (56505560022784).
Almost surely, 2113011120045567 is an apocalyptic number.
113011120045567 is a deficient number, since it is larger than the sum of its proper divisors (1).
113011120045567 is an equidigital number, since it uses as much as digits as its factorization.
113011120045567 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 25200, while the sum is 37.
Adding to 113011120045567 its reverse (765540021110311), we get a palindrome (878551141155878).
The spelling of 113011120045567 in words is "one hundred thirteen trillion, eleven billion, one hundred twenty million, forty-five thousand, five hundred sixty-seven".
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