Base | Representation |
---|---|
bin | 1010010001110011111011… |
… | …0001001010111101001111 |
3 | 1111000101010221001211200202 |
4 | 2210130332301022331033 |
5 | 2440124134140024403 |
6 | 40011354215244115 |
7 | 2244323043220004 |
oct | 244347661127517 |
9 | 44011127054622 |
10 | 11301112033103 |
11 | 366785813a132 |
12 | 132629367963b |
13 | 63c8c87576c9 |
14 | 2b0d962698ab |
15 | 148e7b7c9688 |
hex | a473ec4af4f |
11301112033103 has 4 divisors (see below), whose sum is σ = 11302422619488. Its totient is φ = 11299801446720.
The previous prime is 11301112033091. The next prime is 11301112033129. The reversal of 11301112033103 is 30133021110311.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 11301112033103 - 222 = 11301107838799 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11301112033153) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 655280258 + ... + 655297503.
It is an arithmetic number, because the mean of its divisors is an integer number (2825605654872).
Almost surely, 211301112033103 is an apocalyptic number.
11301112033103 is a deficient number, since it is larger than the sum of its proper divisors (1310586385).
11301112033103 is an equidigital number, since it uses as much as digits as its factorization.
11301112033103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1310586384.
The product of its (nonzero) digits is 162, while the sum is 20.
Adding to 11301112033103 its reverse (30133021110311), we get a palindrome (41434133143414).
The spelling of 11301112033103 in words is "eleven trillion, three hundred one billion, one hundred twelve million, thirty-three thousand, one hundred three".
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