Base | Representation |
---|---|
bin | 110100100111111111… |
… | …1001110000100000001 |
3 | 101210200221100211211011 |
4 | 1221033333032010001 |
5 | 3322421321404213 |
6 | 123525552320521 |
7 | 11110343456026 |
oct | 1511777160401 |
9 | 353627324734 |
10 | 113011122433 |
11 | 43a22917a50 |
12 | 19a9b243141 |
13 | a8702a6b61 |
14 | 568108354d |
15 | 2e1663703d |
hex | 1a4ffce101 |
113011122433 has 8 divisors (see below), whose sum is σ = 123425447040. Its totient is φ = 102620228880.
The previous prime is 113011122431. The next prime is 113011122443. The reversal of 113011122433 is 334221110311.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 113011122433 - 21 = 113011122431 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (113011122431) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5847673 + ... + 5866966.
It is an arithmetic number, because the mean of its divisors is an integer number (15428180880).
Almost surely, 2113011122433 is an apocalyptic number.
It is an amenable number.
113011122433 is a deficient number, since it is larger than the sum of its proper divisors (10414324607).
113011122433 is a wasteful number, since it uses less digits than its factorization.
113011122433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 11715527.
The product of its (nonzero) digits is 432, while the sum is 22.
Adding to 113011122433 its reverse (334221110311), we get a palindrome (447232232744).
The spelling of 113011122433 in words is "one hundred thirteen billion, eleven million, one hundred twenty-two thousand, four hundred thirty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.067 sec. • engine limits •