Base | Representation |
---|---|
bin | 110100100111111111… |
… | …1001111111010110000 |
3 | 101210200221101020020121 |
4 | 1221033333033322300 |
5 | 3322421322130112 |
6 | 123525552420024 |
7 | 11110343520133 |
oct | 1511777177260 |
9 | 353627336217 |
10 | 113011130032 |
11 | 43a22922729 |
12 | 19a9b247614 |
13 | a8702aa458 |
14 | 568108621a |
15 | 2e16639407 |
hex | 1a4ffcfeb0 |
113011130032 has 10 divisors (see below), whose sum is σ = 218959064468. Its totient is φ = 56505565008.
The previous prime is 113011130003. The next prime is 113011130059. The reversal of 113011130032 is 230031110311.
It is a super-2 number, since 2×1130111300322 (a number of 23 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (16), and also a Moran number because the ratio is a prime number: 7063195627 = 113011130032 / (1 + 1 + 3 + 0 + 1 + 1 + 1 + 3 + 0 + 0 + 3 + 2).
It is a junction number, because it is equal to n+sod(n) for n = 113011129988 and 113011130015.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3531597798 + ... + 3531597829.
Almost surely, 2113011130032 is an apocalyptic number.
It is an amenable number.
113011130032 is a deficient number, since it is larger than the sum of its proper divisors (105947934436).
113011130032 is an equidigital number, since it uses as much as digits as its factorization.
113011130032 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7063195635 (or 7063195629 counting only the distinct ones).
The product of its (nonzero) digits is 54, while the sum is 16.
Adding to 113011130032 its reverse (230031110311), we get a palindrome (343042240343).
The spelling of 113011130032 in words is "one hundred thirteen billion, eleven million, one hundred thirty thousand, thirty-two".
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