Base | Representation |
---|---|
bin | 10000011100011111111… |
… | …100010011010001010001 |
3 | 11000001000110200002220022 |
4 | 100130133330103101101 |
5 | 122003432222100423 |
6 | 2223055540353225 |
7 | 144435144024656 |
oct | 20343774232121 |
9 | 4001013602808 |
10 | 1130112300113 |
11 | 3a6306a27835 |
12 | 1630343a5815 |
13 | 827524cc634 |
14 | 3c9aa7c5c2d |
15 | 1e5e43addc8 |
hex | 1071ff13451 |
1130112300113 has 2 divisors, whose sum is σ = 1130112300114. Its totient is φ = 1130112300112.
The previous prime is 1130112300103. The next prime is 1130112300133. The reversal of 1130112300113 is 3110032110311.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1059104440384 + 71007859729 = 1029128^2 + 266473^2 .
It is a cyclic number.
It is not a de Polignac number, because 1130112300113 - 220 = 1130111251537 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1130112300091 and 1130112300100.
It is not a weakly prime, because it can be changed into another prime (1130112300103) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565056150056 + 565056150057.
It is an arithmetic number, because the mean of its divisors is an integer number (565056150057).
Almost surely, 21130112300113 is an apocalyptic number.
It is an amenable number.
1130112300113 is a deficient number, since it is larger than the sum of its proper divisors (1).
1130112300113 is an equidigital number, since it uses as much as digits as its factorization.
1130112300113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54, while the sum is 17.
Adding to 1130112300113 its reverse (3110032110311), we get a palindrome (4240144410424).
The spelling of 1130112300113 in words is "one trillion, one hundred thirty billion, one hundred twelve million, three hundred thousand, one hundred thirteen".
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