Base | Representation |
---|---|
bin | 10101000011001100… |
… | …11001011101011111 |
3 | 1002011121001222212011 |
4 | 22201212121131133 |
5 | 141121042212002 |
6 | 5105222252051 |
7 | 550024016035 |
oct | 124146313537 |
9 | 32147058764 |
10 | 11301132127 |
11 | 487a21591a |
12 | 2234887027 |
13 | 10b143083c |
14 | 792c9a555 |
15 | 4622238d7 |
hex | 2a199975f |
11301132127 has 2 divisors, whose sum is σ = 11301132128. Its totient is φ = 11301132126.
The previous prime is 11301132023. The next prime is 11301132169. The reversal of 11301132127 is 72123110311.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11301132127 - 219 = 11300607839 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11301132098 and 11301132107.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11301132827) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5650566063 + 5650566064.
It is an arithmetic number, because the mean of its divisors is an integer number (5650566064).
Almost surely, 211301132127 is an apocalyptic number.
11301132127 is a deficient number, since it is larger than the sum of its proper divisors (1).
11301132127 is an equidigital number, since it uses as much as digits as its factorization.
11301132127 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 252, while the sum is 22.
Adding to 11301132127 its reverse (72123110311), we get a palindrome (83424242438).
The spelling of 11301132127 in words is "eleven billion, three hundred one million, one hundred thirty-two thousand, one hundred twenty-seven".
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