Base | Representation |
---|---|
bin | 1010010001110100010010… |
… | …1110111100010100000101 |
3 | 1111000101101220101101022111 |
4 | 2210131010232330110011 |
5 | 2440124340300042013 |
6 | 40011412152301021 |
7 | 2244325366661416 |
oct | 244350456742405 |
9 | 44011356341274 |
10 | 11301212112133 |
11 | 36678a9684a79 |
12 | 13263010a1771 |
13 | 63c9133c8178 |
14 | 2b0da567b80d |
15 | 148e8549773d |
hex | a4744bbc505 |
11301212112133 has 2 divisors, whose sum is σ = 11301212112134. Its totient is φ = 11301212112132.
The previous prime is 11301212112089. The next prime is 11301212112137. The reversal of 11301212112133 is 33121121210311.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11013789602209 + 287422509924 = 3318703^2 + 536118^2 .
It is a cyclic number.
It is not a de Polignac number, because 11301212112133 - 213 = 11301212103941 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11301212112137) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5650606056066 + 5650606056067.
It is an arithmetic number, because the mean of its divisors is an integer number (5650606056067).
Almost surely, 211301212112133 is an apocalyptic number.
It is an amenable number.
11301212112133 is a deficient number, since it is larger than the sum of its proper divisors (1).
11301212112133 is an equidigital number, since it uses as much as digits as its factorization.
11301212112133 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 216, while the sum is 22.
Adding to 11301212112133 its reverse (33121121210311), we get a palindrome (44422333322444).
The spelling of 11301212112133 in words is "eleven trillion, three hundred one billion, two hundred twelve million, one hundred twelve thousand, one hundred thirty-three".
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