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1130121313103 = 7115917201593
BaseRepresentation
bin10000011100100000011…
…110101011101101001111
311000001001002122000101202
4100130200132223231033
5122003442024004403
62223100501500115
7144435313443626
oct20344036535517
94001032560352
101130121313103
113a6311023392
1216303741163b
1382754336b73
143c9aba906bd
151e5e508e688
hex107207abb4f

1130121313103 has 4 divisors (see below), whose sum is σ = 1146038514768. Its totient is φ = 1114204111440.

The previous prime is 1130121313073. The next prime is 1130121313127. The reversal of 1130121313103 is 3013131210311.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1130121313103 - 230 = 1129047571279 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1130121313133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7958600726 + ... + 7958600867.

It is an arithmetic number, because the mean of its divisors is an integer number (286509628692).

Almost surely, 21130121313103 is an apocalyptic number.

1130121313103 is a deficient number, since it is larger than the sum of its proper divisors (15917201665).

1130121313103 is an equidigital number, since it uses as much as digits as its factorization.

1130121313103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 15917201664.

The product of its (nonzero) digits is 162, while the sum is 20.

Adding to 1130121313103 its reverse (3013131210311), we get a palindrome (4143252523414).

The spelling of 1130121313103 in words is "one trillion, one hundred thirty billion, one hundred twenty-one million, three hundred thirteen thousand, one hundred three".

Divisors: 1 71 15917201593 1130121313103