Base | Representation |
---|---|
bin | 1010010001110100010101… |
… | …0101000011010001110101 |
3 | 1111000101102121011221000111 |
4 | 2210131011111003101311 |
5 | 2440124400324232013 |
6 | 40011413150343021 |
7 | 2244325550616655 |
oct | 244350525032165 |
9 | 44011377157014 |
10 | 11301222102133 |
11 | 3667904288677 |
12 | 13263044baa71 |
13 | 63c9154b5302 |
14 | 2b0da6b1c365 |
15 | 148e862bc73d |
hex | a4745543475 |
11301222102133 has 2 divisors, whose sum is σ = 11301222102134. Its totient is φ = 11301222102132.
The previous prime is 11301222102113. The next prime is 11301222102151. The reversal of 11301222102133 is 33120122210311.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 7168267279044 + 4132954823089 = 2677362^2 + 2032967^2 .
It is a cyclic number.
It is not a de Polignac number, because 11301222102133 - 233 = 11292632167541 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11301222102113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5650611051066 + 5650611051067.
It is an arithmetic number, because the mean of its divisors is an integer number (5650611051067).
Almost surely, 211301222102133 is an apocalyptic number.
It is an amenable number.
11301222102133 is a deficient number, since it is larger than the sum of its proper divisors (1).
11301222102133 is an equidigital number, since it uses as much as digits as its factorization.
11301222102133 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 432, while the sum is 22.
Adding to 11301222102133 its reverse (33120122210311), we get a palindrome (44421344312444).
The spelling of 11301222102133 in words is "eleven trillion, three hundred one billion, two hundred twenty-two million, one hundred two thousand, one hundred thirty-three".
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