Base | Representation |
---|---|
bin | 1010010001110100101111… |
… | …1100100110001110011111 |
3 | 1111000101201100002211121212 |
4 | 2210131023330212032133 |
5 | 2440130112240212231 |
6 | 40011432154215035 |
7 | 2244331366431524 |
oct | 244351374461637 |
9 | 44011640084555 |
10 | 11301333132191 |
11 | 3667960a23153 |
12 | 132633572447b |
13 | 63c9324bb47b |
14 | 2b0db778114b |
15 | 148e90e0042b |
hex | a474bf2639f |
11301333132191 has 2 divisors, whose sum is σ = 11301333132192. Its totient is φ = 11301333132190.
The previous prime is 11301333132179. The next prime is 11301333132251. The reversal of 11301333132191 is 19123133310311.
It is a weak prime.
It is an emirp because it is prime and its reverse (19123133310311) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11301333132191 - 230 = 11300259390367 is a prime.
It is a super-3 number, since 3×113013331321913 (a number of 40 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11301333132101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5650666566095 + 5650666566096.
It is an arithmetic number, because the mean of its divisors is an integer number (5650666566096).
Almost surely, 211301333132191 is an apocalyptic number.
11301333132191 is a deficient number, since it is larger than the sum of its proper divisors (1).
11301333132191 is an equidigital number, since it uses as much as digits as its factorization.
11301333132191 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4374, while the sum is 32.
The spelling of 11301333132191 in words is "eleven trillion, three hundred one billion, three hundred thirty-three million, one hundred thirty-two thousand, one hundred ninety-one".
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