Search a number
-
+
113013333113 is a prime number
BaseRepresentation
bin110100101000000011…
…1101001110001111001
3101210201002112011022012
41221100013221301321
53322422403124423
6123530111535305
711110401324122
oct1512007516171
9353632464265
10113013333113
1143a2409795a
1219a9bb2a535
13a87089c155
14568149b049
152e16922078
hex1a501e9c79

113013333113 has 2 divisors, whose sum is σ = 113013333114. Its totient is φ = 113013333112.

The previous prime is 113013333101. The next prime is 113013333229. The reversal of 113013333113 is 311333310311.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 109960549609 + 3052783504 = 331603^2 + 55252^2 .

It is an emirp because it is prime and its reverse (311333310311) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 113013333113 - 212 = 113013329017 is a prime.

It is a super-2 number, since 2×1130133331132 (a number of 23 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (113013330113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56506666556 + 56506666557.

It is an arithmetic number, because the mean of its divisors is an integer number (56506666557).

Almost surely, 2113013333113 is an apocalyptic number.

It is an amenable number.

113013333113 is a deficient number, since it is larger than the sum of its proper divisors (1).

113013333113 is an equidigital number, since it uses as much as digits as its factorization.

113013333113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 729, while the sum is 23.

Adding to 113013333113 its reverse (311333310311), we get a palindrome (424346643424).

The spelling of 113013333113 in words is "one hundred thirteen billion, thirteen million, three hundred thirty-three thousand, one hundred thirteen".