Base | Representation |
---|---|
bin | 110100101000000100… |
… | …0000100101011101111 |
3 | 101210201002201202110121 |
4 | 1221100020010223233 |
5 | 3322422420141221 |
6 | 123530114145411 |
7 | 11110402263316 |
oct | 1512010045357 |
9 | 353632652417 |
10 | 113013443311 |
11 | 43a2416272a |
12 | 19a9bb82267 |
13 | a87090a362 |
14 | 56814c927d |
15 | 2e16944a41 |
hex | 1a50204aef |
113013443311 has 4 divisors (see below), whose sum is σ = 113031283552. Its totient is φ = 112995603072.
The previous prime is 113013443219. The next prime is 113013443317. The reversal of 113013443311 is 113344310311.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-113013443311 is a prime.
It is a super-2 number, since 2×1130134433112 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (113013443317) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8910615 + ... + 8923288.
It is an arithmetic number, because the mean of its divisors is an integer number (28257820888).
Almost surely, 2113013443311 is an apocalyptic number.
113013443311 is a deficient number, since it is larger than the sum of its proper divisors (17840241).
113013443311 is an equidigital number, since it uses as much as digits as its factorization.
113013443311 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 17840240.
The product of its (nonzero) digits is 1296, while the sum is 25.
Adding to 113013443311 its reverse (113344310311), we get a palindrome (226357753622).
The spelling of 113013443311 in words is "one hundred thirteen billion, thirteen million, four hundred forty-three thousand, three hundred eleven".
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