Base | Representation |
---|---|
bin | 10000011100100001110… |
… | …001110111111001110011 |
3 | 11000001002121122222020001 |
4 | 100130201301313321303 |
5 | 122004013114333021 |
6 | 2223103001130431 |
7 | 144436000012552 |
oct | 20344161677163 |
9 | 4001077588201 |
10 | 1130143121011 |
11 | 3a6322368a53 |
12 | 163042789a17 |
13 | 82758a01158 |
14 | 3c9b0929d99 |
15 | 1e5e6e4b091 |
hex | 10721c77e73 |
1130143121011 has 2 divisors, whose sum is σ = 1130143121012. Its totient is φ = 1130143121010.
The previous prime is 1130143120991. The next prime is 1130143121131. The reversal of 1130143121011 is 1101213410311.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1130143121011 - 217 = 1130142989939 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1130143121011.
It is not a weakly prime, because it can be changed into another prime (1130143121411) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565071560505 + 565071560506.
It is an arithmetic number, because the mean of its divisors is an integer number (565071560506).
Almost surely, 21130143121011 is an apocalyptic number.
1130143121011 is a deficient number, since it is larger than the sum of its proper divisors (1).
1130143121011 is an equidigital number, since it uses as much as digits as its factorization.
1130143121011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 72, while the sum is 19.
Adding to 1130143121011 its reverse (1101213410311), we get a palindrome (2231356531322).
The spelling of 1130143121011 in words is "one trillion, one hundred thirty billion, one hundred forty-three million, one hundred twenty-one thousand, eleven".
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