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1130143133443 = 2574397444099
BaseRepresentation
bin10000011100100001110…
…001111010111100000011
311000001002121200121021111
4100130201301322330003
5122004013120232233
62223103001304151
7144436000064032
oct20344161727403
94001077617244
101130143133443
113a6322377325
12163042795057
1382758a069cc
143c9b0930719
151e5e6e4eacd
hex10721c7af03

1130143133443 has 4 divisors (see below), whose sum is σ = 1134540577800. Its totient is φ = 1125745689088.

The previous prime is 1130143133437. The next prime is 1130143133489. The reversal of 1130143133443 is 3443313410311.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1130143133443 - 25 = 1130143133411 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1130143133243) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2198721793 + ... + 2198722306.

It is an arithmetic number, because the mean of its divisors is an integer number (283635144450).

Almost surely, 21130143133443 is an apocalyptic number.

1130143133443 is a deficient number, since it is larger than the sum of its proper divisors (4397444357).

1130143133443 is an equidigital number, since it uses as much as digits as its factorization.

1130143133443 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4397444356.

The product of its (nonzero) digits is 15552, while the sum is 31.

Adding to 1130143133443 its reverse (3443313410311), we get a palindrome (4573456543754).

The spelling of 1130143133443 in words is "one trillion, one hundred thirty billion, one hundred forty-three million, one hundred thirty-three thousand, four hundred forty-three".

Divisors: 1 257 4397444099 1130143133443