Base | Representation |
---|---|
bin | 11001101100101010011000… |
… | …000010110100100000001001 |
3 | 112211011122012110001102002012 |
4 | 121230222120002310200021 |
5 | 104303211103444144423 |
6 | 1040212452433545305 |
7 | 32543306616511106 |
oct | 3154523002644011 |
9 | 484148173042065 |
10 | 113020320303113 |
11 | 33014715417403 |
12 | 10814118715235 |
13 | 4b0aa02965152 |
14 | 1dca2d9899aad |
15 | d0edb7d92078 |
hex | 66ca980b4809 |
113020320303113 has 2 divisors, whose sum is σ = 113020320303114. Its totient is φ = 113020320303112.
The previous prime is 113020320303071. The next prime is 113020320303151. The reversal of 113020320303113 is 311303023020311.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 59302751885584 + 53717568417529 = 7700828^2 + 7329227^2 .
It is a cyclic number.
It is not a de Polignac number, because 113020320303113 - 26 = 113020320303049 is a prime.
It is not a weakly prime, because it can be changed into another prime (113020322303113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56510160151556 + 56510160151557.
It is an arithmetic number, because the mean of its divisors is an integer number (56510160151557).
Almost surely, 2113020320303113 is an apocalyptic number.
It is an amenable number.
113020320303113 is a deficient number, since it is larger than the sum of its proper divisors (1).
113020320303113 is an equidigital number, since it uses as much as digits as its factorization.
113020320303113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 972, while the sum is 23.
Adding to 113020320303113 its reverse (311303023020311), we get a palindrome (424323343323424).
The spelling of 113020320303113 in words is "one hundred thirteen trillion, twenty billion, three hundred twenty million, three hundred three thousand, one hundred thirteen".
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