Base | Representation |
---|---|
bin | 10101000011010011… |
… | …10101011011101101 |
3 | 1002011122202202210202 |
4 | 22201221311123231 |
5 | 141121310030013 |
6 | 5105253443245 |
7 | 550034460626 |
oct | 124151653355 |
9 | 32148682722 |
10 | 11302033133 |
11 | 487a780856 |
12 | 2235040525 |
13 | 10b1687991 |
14 | 793052a4d |
15 | 462350858 |
hex | 2a1a756ed |
11302033133 has 4 divisors (see below), whose sum is σ = 11304649440. Its totient is φ = 11299416828.
The previous prime is 11302033081. The next prime is 11302033147. The reversal of 11302033133 is 33133020311.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 11302033133 - 220 = 11300984557 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11302033153) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1301663 + ... + 1310316.
It is an arithmetic number, because the mean of its divisors is an integer number (2826162360).
Almost surely, 211302033133 is an apocalyptic number.
It is an amenable number.
11302033133 is a deficient number, since it is larger than the sum of its proper divisors (2616307).
11302033133 is an equidigital number, since it uses as much as digits as its factorization.
11302033133 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2616306.
The product of its (nonzero) digits is 486, while the sum is 20.
Adding to 11302033133 its reverse (33133020311), we get a palindrome (44435053444).
The spelling of 11302033133 in words is "eleven billion, three hundred two million, thirty-three thousand, one hundred thirty-three".
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