Base | Representation |
---|---|
bin | 10000011100100101011… |
… | …011101000111011101011 |
3 | 11000001020212222100002121 |
4 | 100130211123220323223 |
5 | 122004124311321022 |
6 | 2223113030412111 |
7 | 144440342621545 |
oct | 20344533507353 |
9 | 4001225870077 |
10 | 1130204401387 |
11 | 3a6353a13896 |
12 | 16305b201037 |
13 | 82768608b29 |
14 | 3c9b8b1c695 |
15 | 1e5ec5032c7 |
hex | 107256e8eeb |
1130204401387 has 2 divisors, whose sum is σ = 1130204401388. Its totient is φ = 1130204401386.
The previous prime is 1130204401309. The next prime is 1130204401409. The reversal of 1130204401387 is 7831044020311.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1130204401387 - 231 = 1128056917739 is a prime.
It is not a weakly prime, because it can be changed into another prime (1130204401087) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565102200693 + 565102200694.
It is an arithmetic number, because the mean of its divisors is an integer number (565102200694).
Almost surely, 21130204401387 is an apocalyptic number.
1130204401387 is a deficient number, since it is larger than the sum of its proper divisors (1).
1130204401387 is an equidigital number, since it uses as much as digits as its factorization.
1130204401387 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 16128, while the sum is 34.
Adding to 1130204401387 its reverse (7831044020311), we get a palindrome (8961248421698).
The spelling of 1130204401387 in words is "one trillion, one hundred thirty billion, two hundred four million, four hundred one thousand, three hundred eighty-seven".
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