Search a number
-
+
113021133000 = 23353314129641
BaseRepresentation
bin110100101000010010…
…1011010000011001000
3101210201122012102201220
41221100211122003020
53322431402224000
6123530551042040
711110524531246
oct1512045320310
9353648172656
10113021133000
1143a28535046
1219aa2670320
13a8723a0479
14568252b796
152e174631a0
hex1a5095a0c8

113021133000 has 256 divisors, whose sum is σ = 372891617280. Its totient is φ = 28454400000.

The previous prime is 113021132989. The next prime is 113021133023. The reversal of 113021133000 is 331120311.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is an unprimeable number.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 3798180 + ... + 3827820.

It is an arithmetic number, because the mean of its divisors is an integer number (1456607880).

Almost surely, 2113021133000 is an apocalyptic number.

113021133000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 113021133000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (186445808640).

113021133000 is an abundant number, since it is smaller than the sum of its proper divisors (259870484280).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

113021133000 is a wasteful number, since it uses less digits than its factorization.

113021133000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 29737 (or 29723 counting only the distinct ones).

The product of its (nonzero) digits is 54, while the sum is 15.

Adding to 113021133000 its reverse (331120311), we get a palindrome (113352253311).

The spelling of 113021133000 in words is "one hundred thirteen billion, twenty-one million, one hundred thirty-three thousand".