Base | Representation |
---|---|
bin | 10101000011010100… |
… | …01001000000010101 |
3 | 1002011122220211202221 |
4 | 22201222021000111 |
5 | 141121320111201 |
6 | 5105255302341 |
7 | 550035243433 |
oct | 124152110025 |
9 | 32148824687 |
10 | 11302113301 |
11 | 487a826006 |
12 | 223507a9b1 |
13 | 10b16b530b |
14 | 793073d53 |
15 | 4623694a1 |
hex | 2a1a89015 |
11302113301 has 2 divisors, whose sum is σ = 11302113302. Its totient is φ = 11302113300.
The previous prime is 11302113271. The next prime is 11302113373. The reversal of 11302113301 is 10331120311.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 6897136401 + 4404976900 = 83049^2 + 66370^2 .
It is an emirp because it is prime and its reverse (10331120311) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11302113301 - 221 = 11300016149 is a prime.
It is a super-2 number, since 2×113021133012 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11302113601) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5651056650 + 5651056651.
It is an arithmetic number, because the mean of its divisors is an integer number (5651056651).
Almost surely, 211302113301 is an apocalyptic number.
It is an amenable number.
11302113301 is a deficient number, since it is larger than the sum of its proper divisors (1).
11302113301 is an equidigital number, since it uses as much as digits as its factorization.
11302113301 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54, while the sum is 16.
Adding to 11302113301 its reverse (10331120311), we get a palindrome (21633233612).
The spelling of 11302113301 in words is "eleven billion, three hundred two million, one hundred thirteen thousand, three hundred one".
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