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11302121330341 = 471669144080687
BaseRepresentation
bin1010010001110111101011…
…1011010101011010100101
31111000110202021020110012221
42210131322323111122211
52440133221030032331
640012042312112341
72244360050132362
oct244357273253245
944013667213187
1011302121330341
113668225933086
1213265156956b1
1363ca2989b5ca
142b1050317469
15148eda1e5711
hexa477aed56a5

11302121330341 has 8 divisors (see below), whose sum is σ = 11549507950080. Its totient is φ = 11055022875408.

The previous prime is 11302121330329. The next prime is 11302121330389. The reversal of 11302121330341 is 14303312120311.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 11302121330341 - 215 = 11302121297573 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11302121330321) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 71961901 + ... + 72118786.

It is an arithmetic number, because the mean of its divisors is an integer number (1443688493760).

Almost surely, 211302121330341 is an apocalyptic number.

It is an amenable number.

11302121330341 is a deficient number, since it is larger than the sum of its proper divisors (247386619739).

11302121330341 is a wasteful number, since it uses less digits than its factorization.

11302121330341 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 144082403.

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 11302121330341 its reverse (14303312120311), we get a palindrome (25605433450652).

The spelling of 11302121330341 in words is "eleven trillion, three hundred two billion, one hundred twenty-one million, three hundred thirty thousand, three hundred forty-one".

Divisors: 1 47 1669 78443 144080687 6771792289 240470666603 11302121330341