Base | Representation |
---|---|
bin | 10000011100100101111… |
… | …100011100001101001011 |
3 | 11000001021111011012012011 |
4 | 100130211330130031023 |
5 | 122004134012000021 |
6 | 2223113535000351 |
7 | 144440505663454 |
oct | 20344574341513 |
9 | 4001244135164 |
10 | 1130213000011 |
11 | 3a6358857097 |
12 | 1630620690b7 |
13 | 8276a329884 |
14 | 3c9b9d1a12b |
15 | 1e5ed150de1 |
hex | 10725f1c34b |
1130213000011 has 2 divisors, whose sum is σ = 1130213000012. Its totient is φ = 1130213000010.
The previous prime is 1130212999913. The next prime is 1130213000083. The reversal of 1130213000011 is 1100003120311.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1130213000011 - 215 = 1130212967243 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1130212999955 and 1130213000000.
It is not a weakly prime, because it can be changed into another prime (1130213000711) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565106500005 + 565106500006.
It is an arithmetic number, because the mean of its divisors is an integer number (565106500006).
Almost surely, 21130213000011 is an apocalyptic number.
1130213000011 is a deficient number, since it is larger than the sum of its proper divisors (1).
1130213000011 is an equidigital number, since it uses as much as digits as its factorization.
1130213000011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 18, while the sum is 13.
Adding to 1130213000011 its reverse (1100003120311), we get a palindrome (2230216120322).
The spelling of 1130213000011 in words is "one trillion, one hundred thirty billion, two hundred thirteen million, eleven", and thus it is an aban number.
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