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1130213003331 = 31723963523447
BaseRepresentation
bin10000011100100101111…
…100011101000001000011
311000001021111011100202010
4100130211330131001003
5122004134012101311
62223113535024003
7144440506006236
oct20344574350103
94001244140663
101130213003331
113a6358859635
1216306206b003
138276a32b239
143c9b9d1b41d
151e5ed151da6
hex10725f1d043

1130213003331 has 16 divisors (see below), whose sum is σ = 1664968518144. Its totient is φ = 678320505984.

The previous prime is 1130213003321. The next prime is 1130213003369. The reversal of 1130213003331 is 1333003120311.

It is not a de Polignac number, because 1130213003331 - 226 = 1130145894467 is a prime.

It is a super-2 number, since 2×11302130033312 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1130213003298 and 1130213003307.

It is not an unprimeable number, because it can be changed into a prime (1130213003321) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 481760551 + ... + 481762896.

It is an arithmetic number, because the mean of its divisors is an integer number (104060532384).

Almost surely, 21130213003331 is an apocalyptic number.

1130213003331 is a deficient number, since it is larger than the sum of its proper divisors (534755514813).

1130213003331 is a wasteful number, since it uses less digits than its factorization.

1130213003331 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 963523490.

The product of its (nonzero) digits is 486, while the sum is 21.

Adding to 1130213003331 its reverse (1333003120311), we get a palindrome (2463216123642).

The spelling of 1130213003331 in words is "one trillion, one hundred thirty billion, two hundred thirteen million, three thousand, three hundred thirty-one".

Divisors: 1 3 17 23 51 69 391 1173 963523447 2890570341 16379898599 22161039281 49139695797 66483117843 376737667777 1130213003331