Base | Representation |
---|---|
bin | 11001101100101011010010… |
… | …100000101001100110010100 |
3 | 112211011201201210210012102200 |
4 | 121230223102200221212110 |
5 | 104303220111101420200 |
6 | 1040213134034004500 |
7 | 32543343130143432 |
oct | 3154532240514624 |
9 | 484151653705380 |
10 | 113021301201300 |
11 | 33015079083768 |
12 | 10814351116730 |
13 | 4b0ab2ac4498b |
14 | 1dca38dc73d52 |
15 | d0ee2404d800 |
hex | 66cad2829994 |
113021301201300 has 216 divisors, whose sum is σ = 354685626125376. Its totient is φ = 30102728647680.
The previous prime is 113021301201299. The next prime is 113021301201301. The reversal of 113021301201300 is 3102103120311.
113021301201300 is a `hidden beast` number, since 1 + 1 + 30 + 2 + 130 + 1 + 201 + 300 = 666.
It is an interprime number because it is at equal distance from previous prime (113021301201299) and next prime (113021301201301).
It is a Harshad number since it is a multiple of its sum of digits (18).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (113021301201301) by changing a digit.
It is a polite number, since it can be written in 71 ways as a sum of consecutive naturals, for example, 8025364059 + ... + 8025378141.
Almost surely, 2113021301201300 is an apocalyptic number.
113021301201300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 113021301201300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (177342813062688).
113021301201300 is an abundant number, since it is smaller than the sum of its proper divisors (241664324924076).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
113021301201300 is a wasteful number, since it uses less digits than its factorization.
113021301201300 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 24207 (or 24197 counting only the distinct ones).
The product of its (nonzero) digits is 108, while the sum is 18.
Adding to 113021301201300 its reverse (3102103120311), we get a palindrome (116123404321611).
The spelling of 113021301201300 in words is "one hundred thirteen trillion, twenty-one billion, three hundred one million, two hundred one thousand, three hundred".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.119 sec. • engine limits •