Base | Representation |
---|---|
bin | 11001101100101100001110… |
… | …111000101110000101110011 |
3 | 112211011211100101211000202020 |
4 | 121230230032320232011303 |
5 | 104303224144410102430 |
6 | 1040213422340522523 |
7 | 32543410210051455 |
oct | 3154541670560563 |
9 | 484154311730666 |
10 | 113022314144115 |
11 | 33015548937692 |
12 | 108145943b0443 |
13 | 4b0ac5ca6401c |
14 | 1dca4485d02d5 |
15 | d0ee82e39b10 |
hex | 66cb0ee2e173 |
113022314144115 has 8 divisors (see below), whose sum is σ = 180835702630608. Its totient is φ = 60278567543520.
The previous prime is 113022314144093. The next prime is 113022314144123. The reversal of 113022314144115 is 511441413220311.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 113022314144115 - 25 = 113022314144083 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3767410471456 + ... + 3767410471485.
It is an arithmetic number, because the mean of its divisors is an integer number (22604462828826).
Almost surely, 2113022314144115 is an apocalyptic number.
113022314144115 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
113022314144115 is a deficient number, since it is larger than the sum of its proper divisors (67813388486493).
113022314144115 is an equidigital number, since it uses as much as digits as its factorization.
113022314144115 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7534820942949.
The product of its (nonzero) digits is 11520, while the sum is 33.
Adding to 113022314144115 its reverse (511441413220311), we get a palindrome (624463727364426).
The spelling of 113022314144115 in words is "one hundred thirteen trillion, twenty-two billion, three hundred fourteen million, one hundred forty-four thousand, one hundred fifteen".
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