Base | Representation |
---|---|
bin | 10000011100100110100… |
… | …111101011011010000111 |
3 | 11000001022021111001010222 |
4 | 100130212213223122013 |
5 | 122004144412200341 |
6 | 2223115021534555 |
7 | 144441004221521 |
oct | 20344647533207 |
9 | 4001267431128 |
10 | 1130224334471 |
11 | 3a6364198911 |
12 | 163065a1445b |
13 | 8276c79795b |
14 | 3c9bb62aa11 |
15 | 1e5ee13e44b |
hex | 107269eb687 |
1130224334471 has 2 divisors, whose sum is σ = 1130224334472. Its totient is φ = 1130224334470.
The previous prime is 1130224334399. The next prime is 1130224334497. The reversal of 1130224334471 is 1744334220311.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1130224334471 - 238 = 855346427527 is a prime.
It is a super-3 number, since 3×11302243344713 (a number of 37 digits) contains 333 as substring.
It is a Sophie Germain prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1130224330471) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565112167235 + 565112167236.
It is an arithmetic number, because the mean of its divisors is an integer number (565112167236).
Almost surely, 21130224334471 is an apocalyptic number.
1130224334471 is a deficient number, since it is larger than the sum of its proper divisors (1).
1130224334471 is an equidigital number, since it uses as much as digits as its factorization.
1130224334471 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 48384, while the sum is 35.
Adding to 1130224334471 its reverse (1744334220311), we get a palindrome (2874558554782).
The spelling of 1130224334471 in words is "one trillion, one hundred thirty billion, two hundred twenty-four million, three hundred thirty-four thousand, four hundred seventy-one".
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