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1130240015537 is a prime number
BaseRepresentation
bin10000011100100111100…
…011011111110010110001
311000001100100222201112012
4100130213203133302301
5122004212420444122
62223120342012305
7144441254422103
oct20344743376261
94001310881465
101130240015537
113a6372029276
1216306b117095
1382772ac82a9
143c9bd74d573
151e6006da7e2
hex107278dfcb1

1130240015537 has 2 divisors, whose sum is σ = 1130240015538. Its totient is φ = 1130240015536.

The previous prime is 1130240015501. The next prime is 1130240015573. The reversal of 1130240015537 is 7355100420311.

Together with next prime (1130240015573) it forms an Ormiston pair, because they use the same digits, order apart.

It is a balanced prime because it is at equal distance from previous prime (1130240015501) and next prime (1130240015573).

It can be written as a sum of positive squares in only one way, i.e., 592893840016 + 537346175521 = 769996^2 + 733039^2 .

It is a cyclic number.

It is not a de Polignac number, because 1130240015537 - 212 = 1130240011441 is a prime.

It is not a weakly prime, because it can be changed into another prime (1130240035537) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565120007768 + 565120007769.

It is an arithmetic number, because the mean of its divisors is an integer number (565120007769).

Almost surely, 21130240015537 is an apocalyptic number.

It is an amenable number.

1130240015537 is a deficient number, since it is larger than the sum of its proper divisors (1).

1130240015537 is an equidigital number, since it uses as much as digits as its factorization.

1130240015537 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12600, while the sum is 32.

Adding to 1130240015537 its reverse (7355100420311), we get a palindrome (8485340435848).

The spelling of 1130240015537 in words is "one trillion, one hundred thirty billion, two hundred forty million, fifteen thousand, five hundred thirty-seven".