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11302440001 = 18427613363
BaseRepresentation
bin10101000011010110…
…11000110001000001
31002011200112102220221
422201223120301001
5141121411040001
65105310303041
7550041104056
oct124153306101
932150472827
1011302440001
11487aa29506
1222351b7a81
1310b179ac28
1479311b02d
154623d11a1
hex2a1ad8c41

11302440001 has 4 divisors (see below), whose sum is σ = 11303071792. Its totient is φ = 11301808212.

The previous prime is 11302439999. The next prime is 11302440007. The reversal of 11302440001 is 10004420311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 10004420311 = 18517540283.

It is a cyclic number.

It is not a de Polignac number, because 11302440001 - 21 = 11302439999 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11302440007) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 288255 + ... + 325108.

It is an arithmetic number, because the mean of its divisors is an integer number (2825767948).

Almost surely, 211302440001 is an apocalyptic number.

It is an amenable number.

11302440001 is a deficient number, since it is larger than the sum of its proper divisors (631791).

11302440001 is an equidigital number, since it uses as much as digits as its factorization.

11302440001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 631790.

The product of its (nonzero) digits is 96, while the sum is 16.

Adding to 11302440001 its reverse (10004420311), we get a palindrome (21306860312).

The spelling of 11302440001 in words is "eleven billion, three hundred two million, four hundred forty thousand, one".

Divisors: 1 18427 613363 11302440001