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11302440000 = 2635497971
BaseRepresentation
bin10101000011010110…
…11000110001000000
31002011200112102220220
422201223120301000
5141121411040000
65105310303040
7550041104055
oct124153306100
932150472826
1011302440000
11487aa29505
1222351b7a80
1310b179ac27
1479311b02c
154623d11a0
hex2a1ad8c40

11302440000 has 280 divisors, whose sum is σ = 37792627488. Its totient is φ = 2979840000.

The previous prime is 11302439999. The next prime is 11302440007. The reversal of 11302440000 is 4420311.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11302440007) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 11639515 + ... + 11640485.

Almost surely, 211302440000 is an apocalyptic number.

11302440000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 11302440000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (18896313744).

11302440000 is an abundant number, since it is smaller than the sum of its proper divisors (26490187488).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11302440000 is an frugal number, since it uses more digits than its factorization.

11302440000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1103 (or 1078 counting only the distinct ones).

The product of its (nonzero) digits is 96, while the sum is 15.

Adding to 11302440000 its reverse (4420311), we get a palindrome (11306860311).

The spelling of 11302440000 in words is "eleven billion, three hundred two million, four hundred forty thousand".