Base | Representation |
---|---|
bin | 110100101000011010… |
… | …1110001111011110111 |
3 | 101210201221021111110011 |
4 | 1221100311301323313 |
5 | 3322434002101033 |
6 | 123531223041051 |
7 | 11110606155631 |
oct | 1512065617367 |
9 | 353657244404 |
10 | 113025425143 |
11 | 43a2a9a6874 |
12 | 19aa3ba0187 |
13 | a873243cb7 |
14 | 5682d27a51 |
15 | 2e17a0eccd |
hex | 1a50d71ef7 |
113025425143 has 2 divisors, whose sum is σ = 113025425144. Its totient is φ = 113025425142.
The previous prime is 113025425131. The next prime is 113025425147. The reversal of 113025425143 is 341524520311.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-113025425143 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (113025425147) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56512712571 + 56512712572.
It is an arithmetic number, because the mean of its divisors is an integer number (56512712572).
Almost surely, 2113025425143 is an apocalyptic number.
113025425143 is a deficient number, since it is larger than the sum of its proper divisors (1).
113025425143 is an equidigital number, since it uses as much as digits as its factorization.
113025425143 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 14400, while the sum is 31.
Adding to 113025425143 its reverse (341524520311), we get a palindrome (454549945454).
The spelling of 113025425143 in words is "one hundred thirteen billion, twenty-five million, four hundred twenty-five thousand, one hundred forty-three".
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