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113030219969 is a prime number
BaseRepresentation
bin110100101000100100…
…0000100100011000001
3101210202021022002201022
41221101020010203001
53322441214014334
6123531513515225
711110665006002
oct1512110044301
9353667262638
10113030219969
1143a32681237
1219aa5712b15
13a874232584
1456838151a9
152e1815a82e
hex1a512048c1

113030219969 has 2 divisors, whose sum is σ = 113030219970. Its totient is φ = 113030219968.

The previous prime is 113030219963. The next prime is 113030219971. The reversal of 113030219969 is 969912030311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 64150758400 + 48879461569 = 253280^2 + 221087^2 .

It is a cyclic number.

It is not a de Polignac number, because 113030219969 - 28 = 113030219713 is a prime.

It is a super-2 number, since 2×1130302199692 (a number of 23 digits) contains 22 as substring.

Together with 113030219971, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (113030219963) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56515109984 + 56515109985.

It is an arithmetic number, because the mean of its divisors is an integer number (56515109985).

Almost surely, 2113030219969 is an apocalyptic number.

It is an amenable number.

113030219969 is a deficient number, since it is larger than the sum of its proper divisors (1).

113030219969 is an equidigital number, since it uses as much as digits as its factorization.

113030219969 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 78732, while the sum is 44.

The spelling of 113030219969 in words is "one hundred thirteen billion, thirty million, two hundred nineteen thousand, nine hundred sixty-nine".