Base | Representation |
---|---|
bin | 10101000011011011… |
… | …01110000100001101 |
3 | 1002011201200111210021 |
4 | 22201231232010031 |
5 | 141122040122113 |
6 | 5105331342141 |
7 | 550046232004 |
oct | 124155560415 |
9 | 32151614707 |
10 | 11303051533 |
11 | 4880306a04 |
12 | 2235451951 |
13 | 10b1953397 |
14 | 793239c3b |
15 | 4624a248d |
hex | 2a1b6e10d |
11303051533 has 2 divisors, whose sum is σ = 11303051534. Its totient is φ = 11303051532.
The previous prime is 11303051497. The next prime is 11303051587. The reversal of 11303051533 is 33515030311.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 11252542084 + 50509449 = 106078^2 + 7107^2 .
It is a cyclic number.
It is not a de Polignac number, because 11303051533 - 29 = 11303051021 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11303051498 and 11303051507.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11303051593) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5651525766 + 5651525767.
It is an arithmetic number, because the mean of its divisors is an integer number (5651525767).
Almost surely, 211303051533 is an apocalyptic number.
It is an amenable number.
11303051533 is a deficient number, since it is larger than the sum of its proper divisors (1).
11303051533 is an equidigital number, since it uses as much as digits as its factorization.
11303051533 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2025, while the sum is 25.
Adding to 11303051533 its reverse (33515030311), we get a palindrome (44818081844).
The spelling of 11303051533 in words is "eleven billion, three hundred three million, fifty-one thousand, five hundred thirty-three".
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