11303112203233 has 4 divisors (see below), whose sum is σ = 11308591173888. Its totient is φ = 11297633232580.

The previous prime is 11303112203203. The next prime is 11303112203267. The reversal of 11303112203233 is 33230221130311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11303112203233 - 2¹³ = 11303112195041 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11303112203198 and 11303112203207.

It is not an unprimeable number, because it can be changed into a prime (11303112203203) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2739482233 + ... + 2739486358.

It is an arithmetic number, because the mean of its divisors is an integer number (2827147793472).

Almost surely, 2^{11303112203233} is an apocalyptic number.

It is an amenable number.

11303112203233 is a deficient number, since it is larger than the sum of its proper divisors (5478970655).

11303112203233 is an equidigital number, since it uses as much as digits as its factorization.

11303112203233 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5478970654.

The product of its (nonzero) digits is 1944, while the sum is 25.

Adding to 11303112203233 its reverse (33230221130311), we get a palindrome (44533333333544).

The spelling of 11303112203233 in words is "eleven trillion, three hundred three billion, one hundred twelve million, two hundred three thousand, two hundred thirty-three".