Base | Representation |
---|---|
bin | 1010010001111011011010… |
… | …0010010110011110000011 |
3 | 1111000120022222001222010011 |
4 | 2210132312202112132003 |
5 | 2440142243040222034 |
6 | 40012325435245351 |
7 | 2244423612532261 |
oct | 244366642263603 |
9 | 44016288058104 |
10 | 11303121414019 |
11 | 3668699403816 |
12 | 13267545a9857 |
13 | 63cb58b378b6 |
14 | 2b1107087431 |
15 | 149047de1864 |
hex | a47b6896783 |
11303121414019 has 2 divisors, whose sum is σ = 11303121414020. Its totient is φ = 11303121414018.
The previous prime is 11303121413989. The next prime is 11303121414023. The reversal of 11303121414019 is 91041412130311.
11303121414019 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11303121414019 - 225 = 11303087859587 is a prime.
It is a super-2 number, since 2×113031214140192 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (11303121414059) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5651560707009 + 5651560707010.
It is an arithmetic number, because the mean of its divisors is an integer number (5651560707010).
Almost surely, 211303121414019 is an apocalyptic number.
11303121414019 is a deficient number, since it is larger than the sum of its proper divisors (1).
11303121414019 is an equidigital number, since it uses as much as digits as its factorization.
11303121414019 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2592, while the sum is 31.
The spelling of 11303121414019 in words is "eleven trillion, three hundred three billion, one hundred twenty-one million, four hundred fourteen thousand, nineteen".
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