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11303121414023 is a prime number
BaseRepresentation
bin1010010001111011011010…
…0010010110011110000111
31111000120022222001222010022
42210132312202112132013
52440142243040222043
640012325435245355
72244423612532265
oct244366642263607
944016288058108
1011303121414023
11366869940381a
1213267545a985b
1363cb58b378ba
142b1107087435
15149047de1868
hexa47b6896787

11303121414023 has 2 divisors, whose sum is σ = 11303121414024. Its totient is φ = 11303121414022.

The previous prime is 11303121414019. The next prime is 11303121414037. The reversal of 11303121414023 is 32041412130311.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 11303121414023 - 22 = 11303121414019 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11303121413983 and 11303121414001.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11303121414043) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5651560707011 + 5651560707012.

It is an arithmetic number, because the mean of its divisors is an integer number (5651560707012).

Almost surely, 211303121414023 is an apocalyptic number.

11303121414023 is a deficient number, since it is larger than the sum of its proper divisors (1).

11303121414023 is an equidigital number, since it uses as much as digits as its factorization.

11303121414023 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1728, while the sum is 26.

Adding to 11303121414023 its reverse (32041412130311), we get a palindrome (43344533544334).

The spelling of 11303121414023 in words is "eleven trillion, three hundred three billion, one hundred twenty-one million, four hundred fourteen thousand, twenty-three".