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11303130002 = 25651565001
BaseRepresentation
bin10101000011011100…
…00001001110010010
31002011201211111102112
422201232001032102
5141122100130002
65105333145322
7550050006533
oct124156011622
932151744375
1011303130002
11488035a95a
12223548b242
1310b1980008
1479325a68a
154624ba852
hex2a1b81392

11303130002 has 4 divisors (see below), whose sum is σ = 16954695006. Its totient is φ = 5651565000.

The previous prime is 11303129989. The next prime is 11303130023. The reversal of 11303130002 is 20003130311.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 20003130311 = 43465189077.

It can be written as a sum of positive squares in only one way, i.e., 10465085401 + 838044601 = 102299^2 + 28949^2 .

It is a super-2 number, since 2×113031300022 (a number of 21 digits) contains 22 as substring.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2825782499 + ... + 2825782502.

Almost surely, 211303130002 is an apocalyptic number.

11303130002 is a deficient number, since it is larger than the sum of its proper divisors (5651565004).

11303130002 is an equidigital number, since it uses as much as digits as its factorization.

11303130002 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5651565003.

The product of its (nonzero) digits is 54, while the sum is 14.

Adding to 11303130002 its reverse (20003130311), we get a palindrome (31306260313).

The spelling of 11303130002 in words is "eleven billion, three hundred three million, one hundred thirty thousand, two".

Divisors: 1 2 5651565001 11303130002