11303130023 has 2 divisors, whose sum is σ = 11303130024. Its totient is φ = 11303130022.

The previous prime is 11303129989. The next prime is 11303130043. The reversal of 11303130023 is 32003130311.

It is a strong prime.

It is an emirp because it is prime and its reverse (32003130311) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11303130023 - 2¹⁰ = 11303128999 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11303129983 and 11303130010.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11303130043) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5651565011 + 5651565012.

It is an arithmetic number, because the mean of its divisors is an integer number (5651565012).

Almost surely, 2^11303130023 is an apocalyptic number.

11303130023 is a deficient number, since it is larger than the sum of its proper divisors (1).

11303130023 is an equidigital number, since it uses as much as digits as its factorization.

11303130023 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 162, while the sum is 17.

Adding to 11303130023 its reverse (32003130311), we get a palindrome (43306260334).

The spelling of 11303130023 in words is "eleven billion, three hundred three million, one hundred thirty thousand, twenty-three".