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1130313122221 is a prime number
BaseRepresentation
bin10000011100101011111…
…010011000000110101101
311000001112110112221001011
4100130223322120012231
5122004340124402341
62223131512545221
7144443133005113
oct20345372300655
94001473487034
101130313122221
113a63aa321418
1216308b6b2211
1382784cb3b9a
143c9c933dab3
151e606d2bb81
hex1072be981ad

1130313122221 has 2 divisors, whose sum is σ = 1130313122222. Its totient is φ = 1130313122220.

The previous prime is 1130313122129. The next prime is 1130313122231. The reversal of 1130313122221 is 1222213130311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 751491336996 + 378821785225 = 866886^2 + 615485^2 .

It is a cyclic number.

It is not a de Polignac number, because 1130313122221 - 231 = 1128165638573 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1130313122192 and 1130313122201.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1130313122231) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565156561110 + 565156561111.

It is an arithmetic number, because the mean of its divisors is an integer number (565156561111).

Almost surely, 21130313122221 is an apocalyptic number.

It is an amenable number.

1130313122221 is a deficient number, since it is larger than the sum of its proper divisors (1).

1130313122221 is an equidigital number, since it uses as much as digits as its factorization.

1130313122221 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 432, while the sum is 22.

Adding to 1130313122221 its reverse (1222213130311), we get a palindrome (2352526252532).

The spelling of 1130313122221 in words is "one trillion, one hundred thirty billion, three hundred thirteen million, one hundred twenty-two thousand, two hundred twenty-one".