113032101111131 has 2 divisors, whose sum is σ = 113032101111132. Its totient is φ = 113032101111130.

The previous prime is 113032101111049. The next prime is 113032101111133. The reversal of 113032101111131 is 131111101230311.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 113032101111131 - 2¹⁰ = 113032101110107 is a prime.

It is a super-2 number, since 2×113032101111131² (a number of 29 digits) contains 22 as substring.

Together with 113032101111133, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (113032101111133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56516050555565 + 56516050555566.

It is an arithmetic number, because the mean of its divisors is an integer number (56516050555566).

Almost surely, 2^{113032101111131} is an apocalyptic number.

113032101111131 is a deficient number, since it is larger than the sum of its proper divisors (1).

113032101111131 is an equidigital number, since it uses as much as digits as its factorization.

113032101111131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 54, while the sum is 20.

Adding to 113032101111131 its reverse (131111101230311), we get a palindrome (244143202341442).

The spelling of 113032101111131 in words is "one hundred thirteen trillion, thirty-two billion, one hundred one million, one hundred eleven thousand, one hundred thirty-one".