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11303310131 = 41275690491
BaseRepresentation
bin10101000011011101…
…01101001100110011
31002011202011122111222
422201232231030303
5141122121411011
65105341055255
7550051356641
oct124156551463
932152148458
1011303310131
114880473223
12223555752b
1310b1a13cb9
147932a6191
15462503ddb
hex2a1bad333

11303310131 has 4 divisors (see below), whose sum is σ = 11579000664. Its totient is φ = 11027619600.

The previous prime is 11303310103. The next prime is 11303310133. The reversal of 11303310131 is 13101330311.

11303310131 = T23461 + T23462 + ... + T23501.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 11303310131 - 210 = 11303309107 is a prime.

It is a super-2 number, since 2×113033101312 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11303310133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 137845205 + ... + 137845286.

It is an arithmetic number, because the mean of its divisors is an integer number (2894750166).

Almost surely, 211303310131 is an apocalyptic number.

11303310131 is a deficient number, since it is larger than the sum of its proper divisors (275690533).

11303310131 is an equidigital number, since it uses as much as digits as its factorization.

11303310131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 275690532.

The product of its (nonzero) digits is 81, while the sum is 17.

Adding to 11303310131 its reverse (13101330311), we get a palindrome (24404640442).

The spelling of 11303310131 in words is "eleven billion, three hundred three million, three hundred ten thousand, one hundred thirty-one".

Divisors: 1 41 275690491 11303310131