Base | Representation |
---|---|
bin | 10101000011011101… |
… | …10010100100011001 |
3 | 1002011202012202200102 |
4 | 22201232302210121 |
5 | 141122123111441 |
6 | 5105341345145 |
7 | 550051511024 |
oct | 124156624431 |
9 | 32152182612 |
10 | 11303332121 |
11 | 48804887a4 |
12 | 22355681b5 |
13 | 10b1a21003 |
14 | 7932b01bb |
15 | 46250a69b |
hex | 2a1bb2919 |
11303332121 has 2 divisors, whose sum is σ = 11303332122. Its totient is φ = 11303332120.
The previous prime is 11303332067. The next prime is 11303332151. The reversal of 11303332121 is 12123330311.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 10375459600 + 927872521 = 101860^2 + 30461^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11303332121 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11303332093 and 11303332102.
It is not a weakly prime, because it can be changed into another prime (11303332151) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5651666060 + 5651666061.
It is an arithmetic number, because the mean of its divisors is an integer number (5651666061).
Almost surely, 211303332121 is an apocalyptic number.
It is an amenable number.
11303332121 is a deficient number, since it is larger than the sum of its proper divisors (1).
11303332121 is an equidigital number, since it uses as much as digits as its factorization.
11303332121 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 324, while the sum is 20.
Adding to 11303332121 its reverse (12123330311), we get a palindrome (23426662432).
The spelling of 11303332121 in words is "eleven billion, three hundred three million, three hundred thirty-two thousand, one hundred twenty-one".
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