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113034431407 is a prime number
BaseRepresentation
bin110100101000101100…
…0001000101110101111
3101210202120020001201111
41221101120020232233
53322443303301112
6123532144052451
711111045546152
oct1512130105657
9353676201644
10113034431407
1143a34a98367
1219aa7004127
13a875078451
1456841cdc99
152e186dd5a7
hex1a51608baf

113034431407 has 2 divisors, whose sum is σ = 113034431408. Its totient is φ = 113034431406.

The previous prime is 113034431387. The next prime is 113034431429. The reversal of 113034431407 is 704134430311.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 113034431407 - 211 = 113034429359 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (113034431207) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56517215703 + 56517215704.

It is an arithmetic number, because the mean of its divisors is an integer number (56517215704).

Almost surely, 2113034431407 is an apocalyptic number.

113034431407 is a deficient number, since it is larger than the sum of its proper divisors (1).

113034431407 is an equidigital number, since it uses as much as digits as its factorization.

113034431407 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12096, while the sum is 31.

Adding to 113034431407 its reverse (704134430311), we get a palindrome (817168861718).

The spelling of 113034431407 in words is "one hundred thirteen billion, thirty-four million, four hundred thirty-one thousand, four hundred seven".