Base | Representation |
---|---|
bin | 110100101000101100… |
… | …0001000101110101111 |
3 | 101210202120020001201111 |
4 | 1221101120020232233 |
5 | 3322443303301112 |
6 | 123532144052451 |
7 | 11111045546152 |
oct | 1512130105657 |
9 | 353676201644 |
10 | 113034431407 |
11 | 43a34a98367 |
12 | 19aa7004127 |
13 | a875078451 |
14 | 56841cdc99 |
15 | 2e186dd5a7 |
hex | 1a51608baf |
113034431407 has 2 divisors, whose sum is σ = 113034431408. Its totient is φ = 113034431406.
The previous prime is 113034431387. The next prime is 113034431429. The reversal of 113034431407 is 704134430311.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 113034431407 - 211 = 113034429359 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (113034431207) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56517215703 + 56517215704.
It is an arithmetic number, because the mean of its divisors is an integer number (56517215704).
Almost surely, 2113034431407 is an apocalyptic number.
113034431407 is a deficient number, since it is larger than the sum of its proper divisors (1).
113034431407 is an equidigital number, since it uses as much as digits as its factorization.
113034431407 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12096, while the sum is 31.
Adding to 113034431407 its reverse (704134430311), we get a palindrome (817168861718).
The spelling of 113034431407 in words is "one hundred thirteen billion, thirty-four million, four hundred thirty-one thousand, four hundred seven".
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