1130351333441 has 4 divisors (see below), whose sum is σ = 1233110545584. Its totient is φ = 1027592121300.

The previous prime is 1130351333413. The next prime is 1130351333467. The reversal of 1130351333441 is 1443331530311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1130351333441 - 2¹⁴ = 1130351317057 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1130351333398 and 1130351333407.

It is not an unprimeable number, because it can be changed into a prime (1130351333401) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 51379606055 + ... + 51379606076.

It is an arithmetic number, because the mean of its divisors is an integer number (308277636396).

Almost surely, 2^{1130351333441} is an apocalyptic number.

1130351333441 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

1130351333441 is a deficient number, since it is larger than the sum of its proper divisors (102759212143).

1130351333441 is a wasteful number, since it uses less digits than its factorization.

1130351333441 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 102759212142.

The product of its (nonzero) digits is 19440, while the sum is 32.

Adding to 1130351333441 its reverse (1443331530311), we get a palindrome (2573682863752).

The spelling of 1130351333441 in words is "one trillion, one hundred thirty billion, three hundred fifty-one million, three hundred thirty-three thousand, four hundred forty-one".