Base | Representation |
---|---|
bin | 1010010001111111001000… |
… | …1011110011111010010111 |
3 | 1111000122220201010000201001 |
4 | 2210133302023303322113 |
5 | 2440201320231411023 |
6 | 40013013024244131 |
7 | 2244460453540543 |
oct | 244376213637227 |
9 | 44018821100631 |
10 | 11304122138263 |
11 | 3669062281749 |
12 | 1326993770647 |
13 | 63cc88269616 |
14 | 2b119dd42a23 |
15 | 1490a5bb76ad |
hex | a47f22f3e97 |
11304122138263 has 2 divisors, whose sum is σ = 11304122138264. Its totient is φ = 11304122138262.
The previous prime is 11304122138209. The next prime is 11304122138291. The reversal of 11304122138263 is 36283122140311.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11304122138263 - 213 = 11304122130071 is a prime.
It is a super-3 number, since 3×113041221382633 (a number of 40 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11304122138293) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5652061069131 + 5652061069132.
It is an arithmetic number, because the mean of its divisors is an integer number (5652061069132).
Almost surely, 211304122138263 is an apocalyptic number.
11304122138263 is a deficient number, since it is larger than the sum of its proper divisors (1).
11304122138263 is an equidigital number, since it uses as much as digits as its factorization.
11304122138263 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 41472, while the sum is 37.
Adding to 11304122138263 its reverse (36283122140311), we get a palindrome (47587244278574).
The spelling of 11304122138263 in words is "eleven trillion, three hundred four billion, one hundred twenty-two million, one hundred thirty-eight thousand, two hundred sixty-three".
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