Base | Representation |
---|---|
bin | 110100101000111011… |
… | …0100100111110110011 |
3 | 101210210010020111021101 |
4 | 1221101312210332303 |
5 | 3323002324131233 |
6 | 123533031105231 |
7 | 11111203433443 |
oct | 1512166447663 |
9 | 353703214241 |
10 | 113042411443 |
11 | 43a39548935 |
12 | 19aa9812217 |
13 | a876910770 |
14 | 56852aa123 |
15 | 2e19267c7d |
hex | 1a51da4fb3 |
113042411443 has 4 divisors (see below), whose sum is σ = 121737981568. Its totient is φ = 104346841320.
The previous prime is 113042411441. The next prime is 113042411459. The reversal of 113042411443 is 344114240311.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 113042411443 - 21 = 113042411441 is a prime.
It is a super-3 number, since 3×1130424114433 (a number of 34 digits) contains 333 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (113042411441) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4347785043 + ... + 4347785068.
It is an arithmetic number, because the mean of its divisors is an integer number (30434495392).
Almost surely, 2113042411443 is an apocalyptic number.
113042411443 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
113042411443 is a deficient number, since it is larger than the sum of its proper divisors (8695570125).
113042411443 is an equidigital number, since it uses as much as digits as its factorization.
113042411443 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 8695570124.
The product of its (nonzero) digits is 4608, while the sum is 28.
Adding to 113042411443 its reverse (344114240311), we get a palindrome (457156651754).
The spelling of 113042411443 in words is "one hundred thirteen billion, forty-two million, four hundred eleven thousand, four hundred forty-three".
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